Question

the roots of the quadratic equation x²+7x+12=0 are​

Answer 1

Answer:

solving the question by splitting the middle term method,

x²+3x+4x+12

x(x+3)+4(x+3)

(x+4 )(x+3)

roots are -4,-3

Answer 2

Answer:

Add 7, product 12

Factor 3,4

X

$x^{2} + 4x + 3x + 12 = 0\\ \\ x(x + 4)3(x + 4) = 0 \\ (x + 3)(x + 4) = 0 \\ x + 3 = 0 \: \: \: x + 4 = 0 \\ x = - 3 \: \: \: x = - 4$