Question

the roots of the quadratic equation xsquare+5x-(alpha+1)(alpha+6)=0 where alpha is a constant are​

Answer 1

Step-by-step explanation:

${x}^{2} + 5x - ( \alpha + 1)( \alpha + 6) = 0 \\ {x}^{2} - 5x - { \alpha }^{2} - 6 \alpha - 6 = 0$