Question

The roots of the quadratic equation9/x²-27=25/x²-11​

Answer 1

Answer:

Step-by-step explanation:The roots of the quadratic equation is

9/x²-27 = 25/x²-11

We cross multiply each other

25×(x²-27)= 9(x²-11)

25x²- 675 = 9x²- 99

16x²- 576 = 0

x²-36 =0

( By taking 16 as common )

x²=36

x =√36

x =6

Solved

Answer 2

The correct answer is 6 and -6.

Given: The equation = $\frac{9}{x^{2} -27}=\frac{25}{x^{2} -11}$.

To Find: Roots of quadratic equation.

Solution:

$\frac{9}{x^{2} -27}=\frac{25}{x^{2} -11}$

Cross multiply the terms.

9($x^{2}$ - 11) = 25($x^{2}$ - 27)

$9x^{2} -99=25x^{2}- 675$

$16x^{2} =675-99$

$16x^{2} -576=0$

$x^{2} -36=0$

$x^{2} =36$

x = 6, -6.

Hence, the roots of equation are 6 and -6.

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