Question

The roots of the quadratic euqation x² - 7x + 3 = 0 are:

Answer 1

Answer:

Here a=1, b=-7 and c=3

one root={-b+√(b^2-4ac)}/2a

second root ={-b-√(b^2-4ac)}/2a

={7-√(49-12)}/2

={7-√37}/2

={7-6.08}/2

=0.92/2

=0.46