Question

the roots of (x+1)^2 -7(x+1)+12=0​

Answer 1

Answer:

2, 3 are the roots

Step-by-step explanation:

we have the equation,

(x+1)²-7(x+1)+12=0

on simplifying it,

x²+2x+1-7x-7+12=0

x²-5x+6=0

using splitting the middle term,

x²-2x-3x+6=0

x(x-2)-3(x-2)=0

(x-2)(x-3)=0

so the roots are:-

x = 2, 3

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