Question

The roots of x^2+5z+3=0 are p and q. And, the roots of x^2+bx+c=0 are p^2 and q^2. Find b+c.

Answer 1

Answer:

-15

Step-by-step explanation:

Products of root for second eq. = c/a = $p^{2} q^{2}$

FRom first eq. we have pq=3

therefore c=3^2=6

Now for b,

$p^{2} +q^{2}$= -b

We have p+q = -5 from first eq.

p^{2} +q^{2} = $(p+q)^{2} -2pq$

Subst. the values we get,

p^{2} +q^{2} = 5^2 - (2x3) = 25 -6 =21

Now b = -(p^{2} +q^{2}) = -21

b+c = -21+6 = -15

Answer 2

Step-by-step explanation:

answer and the explanation is give in picture

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