Question

the roots of (x+3)^2-9=0​

Answer 1

$\huge\pink {\underline {\mathbb {Answer}}}$

${(x + 3)}^{2} - 9 = 0$

${(x + 3)}^{2} = 9$

${x}^{2} + 6x + 9 = 9$

9 and 9 will cancel out

${x}^{2} + 6x = 0$

$x(x + 6) = 0$

$x = 0$

$or \: \: x + 6 = 0$

$x = - 6$

•°• roots are 0 and -6

$<marquee >☆☆mark me as brainliest ✌✌</marquee >$

Answer 2

Answer:

(x+3)²-9=0

⇒x²+6x+9-9=0

⇒x²+6x=0

⇒x(x+6)=0

So, the roots are:-

x=0 &  ⇒ x+6=0

           ⇒x=-6

So, the roots are x=0 and x=-6.