Question

The roots of x^3+ 2px^2-px+10=0 are integers and form arithmetic progression. Find the value of (10+p)?

Answer 1

Answer:

5/3

Step-by-step explanation:

3x + 2px×2-px+10=0

3x +2px-px×2=10

3x+px×2=10

3x+px=10÷2

3x+px=5

x+px=5/3