Question

The roots of X^3-2x^2+x-2=0 are

Answer 1

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Step-by-step explanation:

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Answer 2

Answer:

Student Answers

TONYS538 | STUDENT

The equation x^3 - 2x^2 - x + 2 = 0 can be solved using factorization.

x^3 - 2x^2 - x + 2 = 0

x^2(x - 2) - 1(x - 2) = 0

(x^2 - 1)(x - 2) = 0

Use the expansion x^2 - 1 = (x - 1)(x + 1)

(x + 1)(x - 1)(x - 2) = 0

This gives the roots of the equation as -1, 1 and 2Algebra Find the Roots (Zeros) f(x)=x^3-2x^2+x-2

f

(

x

)

=

x

3

−

2

x

2

+

x

−

2

f(x)=x3-2x2+x-2

Set

x

3

−

2

x

2

+

x

−

2

x3-2x2+x-2 equal to

0

0.

x

3

−

2

x

2

+

x

−

2

=

0

x3-2x2+x-2=0

Solve for

x

x.

Tap for more steps...

x

=

2

,

i

,

−

i

x=2,i,-i