The roots of x+kx+k=0 Are real and equal,
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Answered by
3
Answer:
ans. k=4
Step-by-step explanation:
if roots are real and equal
D=0
b^2 -4ac = 0
a = 1, b = k, c = 1
k^2 - 4×1×1 = 0
k^2 - 4 = 0
k^2 = 4
k = √4
k = -+2
k = 2 ,k = -2
Answered by
3
Given x
2
+kx+k
roots are real & equal
∴b
2
−4ac=0
=(k)
2
−4(1)(k)=0
=k
2
−4k=0
=k(k−4)=0
∴ k = 0 or k = 4
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