Question

the roots of x^+kx+k=0 are real and equal fond k​

Answer 1

Answer:

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Answer 2

Answer:

Given x

2

+kx+k

roots are real & equal

∴b

2

−4ac=0

=(k)

2

−4(1)(k)=0

=k

2

−4k=0

=k(k−4)=0

∴ k = 0 or k = 4

Step-by-step explanation:

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