Question

the roots of x²-2ax+(a²-b²)=0 are​

Answer 1

Answer:

ارها (x² - 2ax + a²)_b² =0

=) (x -a) ² − b² = 0 [: (a - b) ² = a² - 2ab + b²

-=) =) { at - b² = (a + b) (a - b)}

=) (x-a +b) (x-a-b)

comparing the sides.

x = a +b = 0

x = a - b

=)

x-α = b = 0 二 atb