Question

The roots of (x2-3x+2)(x)(x-4)=0 are​

Answer 1

$= > (x {}^{2} - 3x + 2)(x)(x - 4) \\ = > (x { }^{2} - 2x - x + 2)(x)(x - 4) \\ = > x(x - 2) - 1(x - 2)(x)(x - 4) \\ = >( x - 1)(x - 2)(x)(x - 4) \\ = > x = 1 \\ = > x = 2 \\ = > x = 4 \\ = > x = 0$