Question

The roots of x²-(a+1)x+b²= 0 are equal. Then which of the following can be the values of a and b?
(a) 5,2
(b) 3,4
(c) 5,-3
(d) 5,4
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Answer 1

Answer:

5,-3

Step-by-step explanation:

hope it helps you

Answer 2

Answer:

a = 5

b = - 3

Step-by-step explanation:

Condition when roots are real and equal:

b² - 4ac = 0

(a+1)² - 4(1)(b²) = 0

a² + 2a + 1 - 4b² = 0

a² + 2a - 4b² = -1

substitute 5,2

5² + 2(5) - 4(2)² = 25 + 10 - 16 = 19 ≠ - 1

substitute 3,4

3² + 2(3) - 4(4)² = 9 + 6 - 64 = - 49 ≠ - 1

substitute 5, - 3

5² + 2(5) - 4(-3)² = 25 + 10 - 36 = -1

=> a = 5

b = - 3

Hope it helps you:)