the roots of x²+ kx +4 =0 are real and equal .find the k?
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Answer:
The values of k=4and -4
Step-by-step explanation:
Given equation is x²+Kx+4=0
On comparing with ax²+bx+c=0
a=1;b=K;c=4
If the given equation has equal and real roots then the discriminant of the given equation is equal to zero.
=>D=b²-4ac=0
=>k²-4(1)(4)=0
=>k²-16=0
=>k²-4²=0
=>(k+4)(k-4)=0
=>k+4 =0 =>K=-4
=>k-4=0=>k=4
The values of k=4and -4
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