Question

the roots of x²+kx+6=0 is real and equal. find k​

Answer 1

Answer:

$k = 2 \sqrt{6}$

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Step-by-step explanation:

${x}^{2} + kx + 6 = 0 \\ \\ since \: the \: roots \: are \: real \: and \\ equal \\ \\ {b}^{2} - 4ac = 0 \\ \\ {k }^{2} - 4 \times 1 \times 6 = 0 \\ \\ {k}^{2} - 24 = 0 \\ \\ {k}^{2} = 24 \\ \\ k = \sqrt{24 } \\ \\ k = 2 \sqrt{6}$

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Answer 2

Answer:

if roots of x2 +Kx +6 is real and equal

Then D=0

b2-4ac= 0

K2-4[1][6]=0

K2-24=0

K2=24

K=2 root 6

Hope it helps