Question

the roots of x²+kx+k=0 are real and equal,find k​

Answer 1

Answer:

If the equation has real and equal roots, then

D = 0

=> b² - 4ac = 0

a=1 , b = k and c =k

(k)²-4(1)(k)=0

k²-4k=0

k(k-4) =0

k=0

and

k-4=0

k=4

Step-by-step explanation:

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Answer 2

Answer:

if x²+kx+k=0 are real value then

D=0

b²-4ac=0

k²-4×1×k=0

k²-4k=0

k(k-4)=0

k=0 or k=4 Ans

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