Question

The roots of x2+kx+k=0 are real equal, find k

Answer 1

Answer:

therefore (x-1)=0

Step-by-step explanation:

x2+kx+k=0

x=1

1(2)+k1+k=0

2+2k=0

2k=-2

k=-2/2

k=-1

Answer 2

Answer:

0 or 4

Step-by-step explanation:

To roots to be real and equal, discriminant of the equation must be 0.

Discriminant of ax² + bx + c = 0 is given by b² - 4ac.   On comparing,

a = 1,   b = k,     c = k

  ⇒ discriminant = 0

  ⇒ k² - 4(1)(k) = 0

  ⇒ k² - 4k = 0

  ⇒ k(k - 4) = 0

  ⇒ k = 0    or  k - 4 = 0

  ⇒ k = 0    or  k = 4