The roots of x2+x +1=0 are
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1.618 & -0.618
Step-by-step explanation:
The given equation clearly does not have 1 as it's root.
Multiply both sides of the the given equation by (x−1) .
This gives you equation x3–1=0 .
1 is the only root of the given cubic. The other two are the complex cube roots of 1.
They are {[math]\[/math] cos(2π/3)+isin(2π/3),cos(4π/3)+isin(4π/3) }.
This can also be obtained by directly applying the quadratic formula.
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