Question

The roots of x² + x - 6 = 0 are​

Answer 1

$\huge\mapsto\pink{\textsf{ \textbf{answer}}}$

${x}^{2} + x - 6 \\ {x}^{2} + 3x - 2x - 6 \\ x(x + 3) - 2(x + 3) \\ (x + 3)(x - 2) \\ \\ { \mathtt{either \: x + 3 = 0 \: \: \: \: so \: \: x = - 3}} \\ { \mathtt{or \: x - 2 = 0 \: \: \: so \: x = 2}}$

$\red{ \mathtt{hence \: the \: roots \: are \: - 3 \: and \: 2}}$

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Answer 2

Answer:

x²+x-6=0

=>x²+3x-2x-6=0

=>x(x+3)-2(x+3)=0

=>(x+3)(x-2)=0

Now,

x+3=0

=>x=-3

Or,

=>x-2=0

=>x=2

Ans: x=-3,2