Question

the roots X1 and X2 of the equation of x square + px + 12 is equal to zero are such that X 1 minus *X 2 is equal to 1 then P is​

Answer 1

Answer:

-7 and 7

Step-by-step explanation:

Since it's the square polynomial we now know that X1+X2 = -p

## 2 * X1 = 1-p

We also know that X1 * X2 = 12

X2 ^ 2 + X2 - 12 = 0

X2 = -4, 3

###X1 = -3, 4

##P = 7, -7

Answer 2

Answer:

p=-(X1+X2)/1=-7 or,+7

Step-by-step explanation:

Given,X1-X2=1. ..(1)

Also, X1*X2=12. .....(2)

(As product of Roots= c/a=12/1=12)

So,

Using (a+b)²=(a-b)²+4ab,

X1+X2(p)=√49=+7or,-7