Math, asked by sarthak2683, 11 months ago

The roots {xi},i=1,2,3,...,6 of x6+ax3+b=0 are such that every |xi|=1. How do you prove that, if b2−a2≥1,a2−3≤b2≤a2+5?. Otherwise, b2−5≤a2≤b2+3?

Answers

Answered by jjks72
0

ohh ok if if of k if of skskekwkoe

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