The rotating drum in a clothes-dryer has a radius of 0.37 m. If the acceleration at the rim of the drum is 29 m/s2, what is the tangential speed of the rim?
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Explanation:
Given The rotating drum in a clothes-dryer has a radius of 0.37 m. If the acceleration at the rim of the drum is 29 m/s2, what is the tangential speed of the rim?
- We know that a = v^2 / R
- So V^2 = a R
- Or V = √a x R
- Or V = √29 m/s^2 x 0.37 m
- Or V = √10.73 m^2 / s^2
- So V = 3.27 m / s
So the tangential speed of the rim is 3.27 m / s
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