Chemistry, asked by manyarao5738, 1 year ago

The rqte of reaction quadruples when temperature changes from 293 k to 313 k calculate the energy of activation of the reaction assuming that it does not change with temperature

Answers

Answered by dattahari09
12

Answer: 52.86 kj/mole

Explanation: logk2/k1=Ea/2.303R(1/T1-1/T2)

K2=4k1

log4k1/k1 =Ea/2.303R X (1/293-1/313)

log4 =Ea/2.303R X (313-293)/293x313

Ea =0.6x2.303x8.314x293x313/20

=52.86 kj/mole

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