Question

the rules s x square + bx + c is equal to zero differ by unity then b square is equal to​

Answer 1

Answer:

$b^{2} = s^{2} + 4sc$

Step-by-step explanation:

$sx^{2} + bx + c = 0$

x = $\frac{-b}{2s}$ ± $\frac{\sqrt{b^{2} - 4sc } }{2s}$

According to the problem:

$\frac{-b}{2s}$ + $\frac{\sqrt{b^{2} - 4sc } }{2s}$ - ($\frac{-b}{2s}$ - $\frac{\sqrt{b^{2} - 4sc } }{2s}$) = 1

=> $\frac{\sqrt{b^{2} - 4sc } }{s}$ = 1

=> $b^{2} - 4sc = s^{2}$

=> $b^{2} = s^{2} + 4sc$