Question

The run scored by the batsman A is 48,
50, 29 , 46, 37,
46, 37, then co-efficient of
variance of the runs score by batsman is​

Answer 1

Answer:

Hello kya kar raha h

your answer is

Answer 2

Given data:

Runs scored are 48, 50, 29, 46 and 37.

To find: Coefficient of variation

Step-by-step explanation:

First we find the mean.

Mean, $\mu$

$=\frac{\sum x}{n}$

$=\frac{48+50+29+46+37}{5}$

$=\frac{210}{5}$

$=42$

Now we find the standard deviation.

Standard deviation, $\sigma$

$=\sqrt{\frac{\sum (x-\mu)^{2}}{n-1}}$

$=\sqrt{\frac{(48-42)^{2}+(50-42)^{2}+(29-42)^{2}+(46-42)^{2}+(37-42)^{2}}{5-1}}$

$=\sqrt{\frac{36+64+169+16+25}{4}}$

$=\sqrt{\frac{310}{5}}$

$=7.87$ (approximately)

Let us find coefficient of variation now.

Coefficient of variation, $CV$

$=\frac{\sigma}{\mu}$

$=\frac{7.87}{42}$

$=0.19$ (approximately)

Answer: coefficient of variation = 0.19