Question

The runner travels 50 m in the original direction (north)plus 30 m in the opposite direction (south). What is the total displacement of the runner?

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Answer 1

Given:-

• Displacement in North Direction ,S1 = 50 m

• Displacement in South Direction ,S2 = 30 m

To Find:-

• Total displacement of the runner ,S

Solution:-

⠀⠀⠀⠀⠀⠀⠀⠀⠀According to the Question

It is given that the runner travels 50 m in the North Direction & 30 m in South Direction . If we consider the North Direction as original direction . Then , we take the displacement of South direction as negative.

Displacement is defined as the shortest distance between two points .

☯ Total Displacement = Displacement in North - Displacement in South

Substitute the value we get

$:\implies$ Total Displacement = S1 - S2

$:\implies$ Total Displacement = 50-30

$:\implies$ Total Displacement = 20 m

• Hence, the total displacement of the runner is 20 metres .

Answer 2

Given:-

• Runner travels in the original direction = 50 m

• Runner travels in the opposite direction = 30 m

To Find:-

• Total displacement of the runner.

Solution:-

As, we know Displacement is the shortest possible distance between the initial point to final point.

${\sf{:\implies\:Displacement = Distance\: travelled\:(in \:North - in \:South)}}$

${\sf{:\implies\:Displacement = 50 - 30}}$

${\bf{:\implies\:Displacement = 20m}}$

Hence, The Total Displacement of the runner is 20 m.

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More we can find:-

Total Distance travelled by runner:-

• 50 + 30 = 80m

Total Distance travelled in North:-

• 50m

Total Distance travelled in South:-

• 30m

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