Question

The runs scored by 9 players of a cricket team are 44, 31, 50, 40, 50, 70, 11, 80, 56 Findthe median score​

Answer 1

Given :

The runs scored by 9 players of a cricket team are 44, 31, 50, 40, 50, 70, 11, 80, 56.

To Find :

The mean.

Solution :

Analysis :

Here we first have arrange the variables in ascending order. Then we have to check that the no of variables are odd or even. Considering it we have to use the correct formula for odd or even and we will get the median.

Required Formula :

$\boxed{\bf Median=\left[\left(\dfrac{n+1}{2}\right)th\ observation\right],n\ is\ odd}$

where,

• n = no of variables

Explanation :

Arranging the runs of 9 players in ascending order,

11, 31, 40, 44, 50, 50, 56, 70, 80.

Hence, n = 9.

Using the required formula,

$\bf Median=\left(\dfrac{n+1}{2}\right)th\ observation$

where,

• n = 9

Substituting the required values,

$\\ :\implies\sf Median=\left(\dfrac{n+1}{2}\right)th\ observation$

$\\ :\implies\sf Median=\left(\dfrac{9+1}{2}\right)th\ observation$

$\\ :\implies\sf Median=\left(\dfrac{10}{2}\right)th\ observation$

$\\ :\implies\sf Median=\left(\cancel{\dfrac{10}{2}}\right)th\ observation$

$\\ :\boxed{\bf Median=5th\ observation}$

From the observations we can see that,

50 is the 5th observation.

So, the median is 50.

Median of the given data is 50.

Explore More :

• Median is the central value of a statistical dara if it is arranged in ascending or descending order.

Median for even no of observations :

$\boxed{\bf Median=\left[\dfrac{n}{2}th\ observation+\left(\dfrac{n+1}{2}\right)th\ observation\right],n\ is\ even}$

where,

• n = no of observations (even)