Question

The runs scored in a cricket match by 11 players are as follows:
6, 15, 120, 50, 100, 80, 10, 15, 8, 10, 10
Find the mean, mode and median of this data.

Answer 1

Answer:

arranging the data

6 , 8 , 10 , 10 ,10 , 15 , 15 , 50 , 80 , 100 , 120

mean=(6+8+10+10+10+15+15+50+80+100+120)/11

=424/11

=38.54

mode=10

median=15

Answer 2

Ascending order of the values:

6, 8, 10, 10, 10, 15, 15, 50, 80, 100, 120

Mean:

$\frac{sum \: of \: all \: values}{number \: of \: values}$

$\frac{6 + 8 + 10 + 10 + 10 + 15 + 15 + 50 + 80 + 100 + 120}{11}$

$\frac{424}{11}$

=38.54

Median:

$\frac{n + 1}{2}th \: term = \frac{11 + 1}{2} th \: term$

$= \frac{12}{2} th \: term = 6 th \: term$

=15

Mode:

Number which occurs maximum number of times

= 10

Hope it helps:)