Question

the runs scored in a cricket match by 11 players is as follows 6,15,120,50,100,80,10,15,8,10,15, find the mode and median of this data​

Answer 1

Answer:

median:- 6,8,10,10,15,15,15,50,80,100,120

= 11+1/2 =12/2 =6 वाँ पद

median = 15

Mode = 15 ans.

Answer 2

Run scored in a cricket match by 11 players is as follow:

⠀

$:\implies\sf 6, 15, 120, 50, 100, 80, 10, 15, 8, 10, 15.$

⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

First of all,

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☯ We have to arrange this list Ascending order:

⠀⠀⠀

$:\implies\sf \red{6, 8, 10, 10, 15, 15, 15, 50, 80, 100, 120}$

${\underline{\sf{\bigstar\;Mode\;:}}}$

• The mode is the value that appears most frequently in a data set.

⠀⠀⠀

Here, 15 appears most frequently frequently in given data set.

⠀⠀⠀

$\therefore\;{\underline{\sf{Hence,\;15\;is\;the\;mode\;of\;given\;data.}}}$

⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

${\underline{\sf{\bigstar\;Median\;:}}}$

• The middle value of a series of numbers arranged in order of size.

⠀⠀⠀

$\sf Median \begin{cases} & \sf{\dfrac{n}{2} \qquad if\;n\;is\;even} \\ \\ & \sf{ \dfrac{(n + 2)}{2}^{th}\qquad if\;n\;is\;odd} \end{cases}$

Therefore,

⠀⠀⠀

$\qquad\qquad:\implies\sf \dfrac{(11 + 1)}{2}^{th}$

$\qquad \qquad \: \: \: :\implies\sf \dfrac{(12)}{2}^{th}$

$\quad \quad:\implies\sf 6^{th} \;Observation$

$\therefore\;{\underline{\sf{Hence,\;15\;is\;the\;median\;of\;given\;data.}}}$