Question

The runs scored in a cricket match by 11 players is as follows:
6,15,120,50,100.80.10.15,8,10,15
Find the mean, mod and median.

plz ​

Answer 1

Answer:

Arranging in ascending 6,8,10,10,15,15,15,50,80,100,102

Mean = 6+8+10+10+15+15+15+50+80+100+102/11

= 492 /11

= 39

Mode = 15 ( as 15 is coming 3 times )

Median = 11 + 2 (observation)/2

=12/2 observation

= 6 observation

Thus the sixth observation is 15

Median = 15

Therefore, Mean = 39

Median = 15

Mode = 15

Answer 2

$\huge \bf \color{green} \mathfrak{Question : - }$

The runs scored in a cricket match by 11 players is as follows:

6, 15, 120, 50, 100, 80, 10, 15, 8, 10, 15

• Find the mean, mode and median.

$\huge \bf \color{blue} \mathfrak{Solution : - }$

6, 15, 120, 50, 100, 80, 10, 15, 8, 10, 15

Finding Mean,

The Mean

= Sum of Total Observation/Number of Observation

→ The Mean

= (6 + 15 + 120+ 50+ 100+ 80+ 10+ 15+ 8+ 10+ 15)/11

→ The Mean = 429/11

→ The Mean = 39

Finding Median,

Step 1

Arrange in Ascending or Descending Order.

As

6, 8, 10, 10, 15, 15, 15, 50, 80, 100, 120

Step 2

Finding The Number of Observation.

As

There are 11 Numbers.

So,

We put Formula (n + 1)/2 th Term

The Median = (n + 1)/2 th Term

→ The Median = (11 + 1)/2 th Term

→ The Median = 12/2 th Term

→ The Median = 6th Term

→ The Median = 15

Finding Mode,

The Frequency of 6 = 1

The Frequency of 8 = 1

The Frequency of 10 = 2

The Frequency of 15 = 3

The Frequency of 50 = 1

The Frequency of 80 = 1

The Frequency of 100 = 1

The Frequency of 120 = 1

The Mode = Highest Frequency

The Mode = 15

$\huge \bf \color{orange} \mathfrak{Answer : - }$

• The Mean = 39
• The Median = 15
• The Mode = 15