Question

the rupture of air medium occurs at E=3×10^6 v/m. the maximum charge that can be fine to a sphere of diameter 5m will be​

Answer 1

Answer:

Explanation:

Given The rupture of air medium occurs at E=3×10^6 v/m. the maximum charge that can be held  to a sphere of diameter 5 m will be

The intensity at which the electrons in the material can no longer be bound by nuclei is the electric breakdown intensity.

The maximum charge carried by air is Q.

Now the electric field intensity at the surface of the sphere of radius r is given by  

E = K Q/r^2

Q = Er^2 / K

d = 5, r = 5 / 2

   = 3 x 10^6 x 25 / 9 x 10^9 x 4

  =  25 / 12 x 10^-3

 Q = 2.0833 x 10^-3 C