the safety limit of an elevator is 72 kg.find the maximum number of bags it can carry if the weight of 5 bags is 9 kg each...( direct and inverse variation) plz give correct answer by step by step explanation.. and give fast plz..
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Answer:
weight of 5 bags=9kg
weight of 1 bag=9/5kg
=>no. of bags to carry =72÷9/5
=72×5/9
=40 bags
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