Question

The salary of a man increase by 10% in first year, then by 20% in second year and then by 25% in third year. If the last increase is equivalent to an increase of Rs. 6600, then what is the equivalent of second increase?
A) Rs.2000
B) Rs.2200
C) Rs.4000
D) Rs.4400

Answer 1

Let john's initial salary be ₹100

1st year increment=25% of 100=₹25

salary after 1st increment=100+25=₹125

2nd year increment=20% of 125=₹25

salary after 2nd increment=125+25=₹150

In third year his salary becomes twice of his initial salary i.e., ₹200 (2x100).That means in 3rd year his salary increased by (200-150) ₹50

Therefore percentage of increment in salary in 3rd year=50/150×100=33.33%.
plz mark as BRAINLIEST

Answer 2

let intial salary of a man is 100

now, first increment in first year salary is 10%of 100=10/100*100=10

therefore, first increment salary is 110

second increment of salary is 110+20%of 110=132

third increment of salary is 132+25%of 132=165

now, last increment is 165-132=33=6600

1=200

since second increment is 132-110=22

therefore 22(1)=22(200)=4400.