Math, asked by keshav06madhav, 11 months ago

the salary of an employee is a school was increased by 8% if his present salary is ₹ 9500 what was the salary before increment​

Answers

Answered by TigerMan28
1

Answer:₹8796.3

Step-by-step explanation:

Salary before increment=100*9500/108

=25*9500/27

=25*351.85

=₹8796.30

Answered by Battleangel
6

Let the initial salary of X

X+8% of X =9500

 \frac{x}{1}  \times  \frac{100}{100}  +  \frac{8}{100}  \times x = 9500

 \frac{100}{100}  +  \frac{8x}{100}  = 9500

 \frac{108x}{100}  = 9500 \\ x = 9500 \times  \frac{100}{108}

x = 9500 \times  \frac{50}{54}

x = 9500 \times  \frac{25}{27}

x = \frac{237500}{27}

X=8796.29

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