Question

the salt of an oxyacid of metal M contains two sulphur and six oxygen atoms. what will be the formula of the base formed by the metal and why?​

Answer 1

Let the formula of the salt of an oxyacid of a metal M containing one sulphur and four oxygen atom be MSO4

​It is a neutral molecule therefore total valency should be zero. Let the valency of metal ion be x, the valency of S is +6 and of O is −2

therefore, x+6+4×(−2)=0

or x=+2

It is a bivalent metal ion. The base of this metal will have a formula as

Ma(OH)b

Also, it is a neutral molecule therefore total valency should be zero. valency of H is +1 and of O is −2

therefore, 2a+b(1−2)=0

or b=2a, thus formula is M1(OH)2 or M(OH)2

​  

Answer 2

Answer:

M(OH)^2

Explanation:

The formula of the salt of an oxyacid of a metal M contains 1 sulphur and 4 oxygen atom be = MSO 4

it is neutral so the valency should be zero.

we will take valency of metal ion be x, valency of S is = +6 and of O is −2

therefore, x+6+4×(−2)=0

or x=+2

Base of this metal will have formula as M

a

(OH)b

it is a neutral molecule so total valency is zero. valency of H = +1 and of O = −2

so, 2a+b(1−2)=0

or b=2a, thus the formula is M1

so the answer will be M(OH)^2