the salt of an oxyacid of metal M contains two sulphur and six oxygen atoms. what will be the formula of the base formed by the metal and why?
Answers
Let the formula of the salt of an oxyacid of a metal M containing one sulphur and four oxygen atom be MSO4
It is a neutral molecule therefore total valency should be zero. Let the valency of metal ion be x, the valency of S is +6 and of O is −2
therefore, x+6+4×(−2)=0
or x=+2
It is a bivalent metal ion. The base of this metal will have a formula as
Ma(OH)b
Also, it is a neutral molecule therefore total valency should be zero. valency of H is +1 and of O is −2
therefore, 2a+b(1−2)=0
or b=2a, thus formula is M1(OH)2 or M(OH)2
Answer:
M(OH)^2
Explanation:
The formula of the salt of an oxyacid of a metal M contains 1 sulphur and 4 oxygen atom be = MSO 4
it is neutral so the valency should be zero.
we will take valency of metal ion be x, valency of S is = +6 and of O is −2
therefore, x+6+4×(−2)=0
or x=+2
Base of this metal will have formula as M
a
(OH)b
it is a neutral molecule so total valency is zero. valency of H = +1 and of O = −2
so, 2a+b(1−2)=0
or b=2a, thus the formula is M1
so the answer will be M(OH)^2