Question

The same as a cuboidal tick of silver i-10368 cm
direstors are in Hel ratoi 3:2:1
(i) the dimensions of the block
(a) the diagonal of the block
(111) the cost of gold polishing its entire surface at 050 per chi​

Answer 1

sorry brother the first and main line was not written properly thats why anybody is not able to answer

Answer 2

Answer:

Answer :-

i) Dimensions of Cuboid :-

• Length, l = 36 cm

• Breadth, b = 24 cm

• Height, h = 12 cm

ii) Cost of Polishing entire surface

= ₹ 1584

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★ Concept :-

Here the concept of Volume and Total surface area of Cuboid are used.

=> Volume = l × b × h

=> Total Surface Area = 2(lb+bh+lh)

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★ Solution :-

Given,

» The dimensions of cuboid are in ratio of 3:2:1

» Volume of cuboid = 10368 cm³

Then,

▶Let the length (l) of the cuboid be 3x

▶Let the breadth (b) of the cuboid be 2x

▶Let the height (h) of the cuboid be 1x

where x is the constant by which all teh dimensions are multiplied.

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By applying the length, breadth and height in the formula of Volume, we get,

✒ Volume = length × breadth × height

✒ 3x × 2x × 1x = 10368

✒ 6x³ = 10368

✒ x³ = 10368/6 = 1728

✒ x = ³√1728 = 12

Hence, x = 12 .

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By applying the value of x, in length, breadth and height, we get,

▶ Length, l = 3x = 3(12) = 36 cm

▶Breadth, b = 2x = 2(12) = 24 cm

▶Height, h = 1x = 1(12) = 12 cm

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In order to find the total cost of polishing we must multiply the total area to be painted with the rate of painting an area.

☞ Total Cost = Area to be painted × Rate

Let us find the area to be painted. In order to find the area to be painted, we must take total surface area of solid.

→ T.S.A. = 2(lb + bh + lh)

→ T.S.A. = 2(36×24 + 24×12 + 36×12)

→ T.S.A. = 2(864 + 288 + 432)

→ T.S.A. = 2 × 1584

→ T.S.A. = 3168 cm²

Hence, we get total surface to be painted = 3168 cm².

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• Rate of Painting per area = ₹ 0.50 per cm²

Then,

✏ Total Cost of Painting = 3168 × 0.5

✏ Total Cost of Painting = ₹ 1584

Hence, we get the total cost of painting the cuboid = ₹ 1584.

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★ More to know :-

• Volume of Cube = (Side)³

• Volume of cylinder = πr²h

• Volume of Sphere = 4/3 (πr³)

• Volume of cone = ⅓(πr²h)