Chemistry, asked by Gagan7957, 10 months ago

The same current passed through solution of cuso4 and agcl how much silver will be obtained in the same time in which 0.35 gram of cu were obtained

Answers

Answered by ishmeetkaurarora24
1

Explanation:

W1/E1=W2/E2

W1=0.35

E1=0.35E1=63.5/2=31.25 {E=molar mass/n factor}

W2=?

E2=107.88

0.35/31.25=W2/107.88

W2=1.188g

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Answered by rawatkashish02
0

Answer:

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