Question

the same current was passing through acidulated water and a solution of the salt of a metal. it liberated 55.30 cc of h2 gas at 17 degrees celsius and 730 mmHg the mass of metal deposited 0.0397 gm and the specific heat of the metal 0.236. find the formula of the metal sulfate

Answer 1

Answer:

Acidulated water and a solution of the salt of a metal.

Explanation:

0.236 - 0.0397 is 0.001

So, answer is 0.001