Question

The same digit occurs in the boxes in the number 34_ _ 78. The difference in the place values of those digits is 5400. which digit should replace the boxes?
a)4 b)5 c)6 d)7

those who know the answer please tell in explanation.
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Answer 1

Answer:

(i)Difference between 4000 and 400 is 3600.

(ii) difference between 5000 and 500 is 4500.

(iii)difference between 6000 and 600 is 5400.

(iv) difference between 7000 and 700 is 6300.

Therefore the digit that occurs in the box is (c)6

Step-by-step explanation:

The first box in 34_ _78 has place value of 1000x.

The second box in 34_ _78 has place value of 100x.

(i)If digit in the boxes is 4: first place value is 4000 and second place value is 400, 4000-400=3600.(which is the wrong difference value)

(ii)If digit in the boxes is 5: first place value is 5000 and second place value is 500, 5000-500=4500.(which is the wrong difference value)

(iii)If digit in the boxes is 6: first place value is 6000 and second place value is 600, 6000-600=5400.(which is the right difference value)

(iv)If digit in the boxes is 7: first place value is 7000 and second place value is 700, 7000-700=6300.(which is the wrong difference value)

Therefore, the digit in boxes is (c)6.

Answer 2

Answer:

Option c.) 6 is the correct answer.

Explanation:-

Let the unknown number be x and y respectively.

So it will be like -- 3 4 x y 7 8

In which x is the digit at the thousand place and y is the digit at the hundred place...

It is given that x=y

And the difference in place values of these digits is 5400

$(1000x) - (100x) = 5400 \\ \\ 900x = 5400 \\ \\ x = \frac{5400}{900} \\ \\ x = 6$

Therefore the missing digit is 6.

Since x=y

The required number will be 3 4 6 6 7 8

Hope it helped you..

Thank you !!!