The same quantity of electricity is passed through two cells one containing AlCl3 solution and the other containing ZnCl2
solution. If 0.04 mole of Al is produced in the first cell, the number of moles of Zn produce in the second cell will be
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in this question apply the basic formula that says:
no. of moles * n factor = Q/96500
case 1 : for alcl₃ n factor for Al = 3
0.04 * 3 = Q/96500
therefore Q = 0.12 * 96500 -----------(1)
case 2 : for ZnCl₂ n factor for Zn = 2
no. of moles * 2 = Q/96500
now we know that Q is same ...so put the value in 2 equation
no.of moles *2 = (0.12 * 96500)/96500
no. of moles *2 = 0.12
no if moles of Zn = 0.06
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