The same retarding force is applied to stop a train. The train stops
after 80 m. If the speed is doubled, then the distance will be
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Answer:
320 m
Explanation:
let assume the retarding acceleration on train by force is 'a'.
Now in case 1
by using the equation v^2 - u^2 = 2as
we get the value of u (initial velocity) = 8 root 10
Now in case 2 (when velocity is doubled)
now velocity is doubled, so initial velocity of train becomes 16 root 10
by using the equation v^2 - u^2 = 2as
we get the value of displacement = 320 m
note: as given in the question retardation is same in both cases.
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