Question

the sample 6.8 g of methane is burnt with 4.48 L of O2 at STP. Find out the volume of CO2 gas produced at STP​

Answer 1

Answer:

2.24 l

Explanation:

Methane combustion reaction can be written as:

CCH4 + 2O2 → CO2 + 2H2O

moles of O2 gas=4.48/22.4 =0.2 moles

2 moles of O2 produces 1 mole of CO2

0.2 moles of O2 produces 0.1 mole of CO2

Volume of CO2 produced=0.1×22.4=2.24 litres

Answer 2

Answer:

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Explanation:

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