The sample space of an experiment consists of five simple events:
E1, E2, E3, E4 and E5. These events are mutually exclusive. The probabilities of occurrence of these events are P(E1) = .20, P(E2) = .15, P(E3). 25, P(E4) = .30, P(E5) =.10. Several compound events can be defined for this experiment. They are: F= {E1, E2, E3}, G= {E1, E3, E5}, H= {E4, E5}. Determine
(i) P(G’) (ii) P(F (iii) P(G (iv) P(F (v) P(F
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Step-by-step explanation:
Since E
1
, E
2
and E
3
are mutually exclusive and exhaustive events of the experiment, the sum of the probabilities of the three events must be equal to 1. Also, the probability of an event cannot be negative.
In option C, probability of event 2 is negative, i.e P(E
2
)<0. Hence option C cannot be correct.
In option D, sum of probabilities P(E
1
)+P(E
2
)+P(E
3
)=0.9
=1. Hence option D cannot be correct.
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