Question

The satellite of mass m moving in a circular orbit of radius r around the earth has K.E. ‘’. Then its angular momentum will be

Answer 1

Answer:

Explanation:

Given E = 1/2 mv²

v = √(2E/m)

We know that angular momentum

       L = mvr  = mr√(2E/m)

          = √2mr²E

Answer 2

Explanation:

$ke = \frac{1}{2} m {v}^{2}$

$\frac{1}{2} mr {}^{2} omega {}^{2}$

V=r*omega

$ke = \frac{1}{2} mr {}^{2} omega {}^{2}$