Question

The savings of three friends A, B and C are in the ratio 6:7:12. A, B
and C spend 80%, 60% and 70% of their salaries respectively. Find the
salary of C, if the sum of the salaries of the three persons is Rs.70,000?​

Answer 1

Answer:

Let friends be A,B,C

A:B:C=6:7:12

6X:7X:12X

6X:7X:12X=70,000

by solving we get X=2800

A=6*2800=16,800

B=7*2800=19600

C=12*2800=33600.

Answer 2

Answer:

Step-by-step explanation:

Let X,y,z salary of A,B,C respectively.

So X + y + z = 70000

Spending= 80%, 60%, 70% of their respective salary

So A spends= 80%x

B spends = 60%y

C spends= 70%z

Now savings of A = (x-80%x)=20%x

Savings of B = 40%y

Savings of C = 30%z

Since savings are in ratio = 6:7:12

20%x : 40%y : 30%z= 6:7:12

20%x = 6 times p (where p is a common factor)

40%y= 7p

30%z=12p

X/5=6p

X=30p

Similarly 2/5y=7p

Y=17.-5p

3/10z=12p

z=40p. Gives salary of each.

So 30p+17.5p+40p = 70000

87.5p = 70000

So find p and hence respective salaries.