Question

the scalar product of two vector of magnitude 2, 4 is 4 angle between them is​

Answer 1

Answer:

60°

Explanation:

ABcosθ=4

8cosθ=4

cosθ=½

θ=60°

Answer 2

Given :  scalar product of two vector of magnitude 2, 4 is 4

To Find :  angle between vectors

Solution:

Scaler product of Two vectors A & B

= | A | |B | Cosα

| A | = magnitude of one vector

| B | = magnitude of another vector

α  is the angle between vectors

| A | = 2

| B |  4

angle between vectors  = α

2 * 4 Cosα = 4

=> 2  Cosα = 1

=> Cosα = 1/2

=> Cosα =  Cos 60°

=> α =   60°  

Learn More:

Write formula for dot product.If xi + yj, then find its magnitude ...

https://brainly.in/question/23144792

If vector A = 2i + 3j - k and vector B = 4i + 6j - 2k; where i, j and ka re ...

https://brainly.in/question/11911828