The scalar product of two vectors is 5√3
and magnitude of their vector product in 5.
find the angle between them [Ans:30]
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Explanation:
let vectors = A and B
Scalar product=ABcosTheta=5√3
Vector product=ABsintheta=5
Divide the scalar prpduct by vector product.
So,ABsintheta/ABCos theta=5√3/5
Tantheta =1/√3. (Sintheta/Costheta=Tan theta)
theta=30°
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