Question

The scale of spring balance reading from 0 to 10 kg is 37cm long. A body suspended from the balance is found to oscillate vertically with a frequency of 10/π Hz. Calculate the mass of the body attached to the spring.​

Answer 1

Answer:

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Explanation:

Time period T =2π

k

m

=0.1×π

Angular velocity ω=

T

2π

=20rad/s

for 'k' the spring constant at maximum reading x=0.25 m extension:

M=10kg

Mg=−kx

k- spring constant ; g -acceleration due to gravity

k=392.4N/m

Now

2π

k

m

=0.1×π

putting the value of k .

m=0.98kg