Question

The school cafeteria sells two types of wraps vegetarian and chicken the vegetarian wrap costs $1.00 and the chicken wrap costs $3.40 today they made $266.20 from the 103 wraps sold. How many wraps sold were vegetarian?​

Answer 1

Answer :-

• we asume that,
• Let the count of vegetarian wraps be a
• Let the count of chicken wraps be b

Given :-

• $1.00a + $3.40b = $266.20
• a + 3.4b = 266.2 ___________( 1 )

Given :-

• count of vegetarian wraps + count of chicken wraps = 103
• a + b = 103 __________(2)

• substracting equation (2) from ( 1 )
• ( a + b ) – ( a + 3.4b ) = 103 – 266.2
• b – 3.4 b = – 163.2
• – 2.4 b = – 163.2
• 2.4b = 163.2
• b = 163.2 / 2.4
• b = 68

• Now we put the value of b in equation (2)
• a + b = 103
• a + 68 = 103
• a = 103 – 68
• a = 35

• Hence answer :-
• The school cafeteria sold 35 vegetable wraps.

I hope it helps you ❤️✔️

Answer 2

Let x = number of vegetarian

y = number of chicken

Then x + y = 70

1x + 1.8y = 98.8

Subtracting the second equation from the first, we get

-0.8 y = -28.8.

Divide both sides by -0.8 to obtain y = 36. So, x = 70 - 36 = 34.

I hope that it will help you